JSSC ANM Vacancy 2019: Advertisement of Jharkhand A.N.M Competitive Examination 2019-20 Regular and Backlog Recruitment notification has been released recently. Government of Jharkhand, Jharkhand Staff Selection Commission (JSSC) invites online application from eligible Nursing / ANM qualified candidates for total vacancy of 1985 to be filled through JSSC ANM Competitive Examination. The last date for registration of online applications is 4th October 2019.
Jharkhand JSSC JANMCE 2019 Examination:
|
Name of the Post |
Total Vacancies |
|
ANM (Regular) |
1698 |
|
ANM (Backlog) |
287 |
Age Limit: Minimum - 18 years; Maximum – 38 years for General and 40 years for Reserved categories.
Pay Scale: ₹ 5200 - 20200 + Grade Pay ₹ 2400/-
Educational Qualification: Minimum 10th class (Matriculation) Pass with minimum 45% marks. Candidates should have passed Auxiliary Nurse Midwife (ANM) certification.
Application Fee: ₹ 1200/- for General (OC) and OBC category candidates; ₹ 300/- for Reserved category candidates. The fee should be made through online payment mode using Net-banking/ Credit or Debit Card. No fee for PWD / Physically challenged candidates.
Selection Process: JANMCE 2019 Competitive Examination
How to Apply: Online Application Form For JANMCE-2019 available at JSSC Official website. The online registration will be made through jssc.cbtexam.in on or before 04/10/2019.
Help Desk: For any queries / clarification contact phone Number - 9453827207, 9455874494 (OR) email to helpdesk.jssc2019@gmail.com.
| Regular Notification >> |
| Backlog Notification >> |
| Online Registration >> |
Important Dates:
Closing date for Online Registration -> 4th October 2019
Last date of Making payment through Online/ Offline Mode -> 10th October 2019
Last date of uploading Photograph and Signature -> 13th October 2019
Correction in Application Form -> 14th October 2019 to 16th October 2019
Tentative Examination date -> First Week of November 2019
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by Admin | Last Updated on 2020-03-04T05:28:53Z
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